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to remember the multiplication table, consider the sum of the multiplicand and multiplier.
Remember the value for the sum of 10 (all other values multiplication table) with basic techniques of Vedic mathematics.
The method we follow here is very simple to understand and easy to follow.
The method is based on “Nikhilam” Sutra of Vedic mathematics.
method will be apparent from the following examples
Example 1: ..
Suppose we have to find a 9 x 6
First write one below the other
9
6
Then we reduce numbers from 10 and write the value (09/10 = 1; 10 -6 = 4) to the desired character with ‘-‘ to between
9 -. 1
6-4
The product has two parts. The first part is Cross difference (here it is 9-4 = 6-1 = 5).
The second part is vertical product the right digits (here: 1 x 4 = 4)
We write parts separated by a slash
9 – .. 1
6-4
—–
5/4
—–
So 9 x 6 = 54
Let us see. one example
Example 2 :.
Suppose we have to find the 8 x 7
First write one below the other
8
7
Then we reduce numbers from 10 and write values (8.10 = 2; 10-7 = 3) to the desired character with ‘-‘ to between
8 -. 2
7-3
The product has two parts. The first part is Cross difference (here it is 8-3 = 7-2 = 5).
The second part is vertical product the right digits (here it is 2 x 3 = 6)
We write parts separated by a slash
8 – .. 2
7-3
—–
5/6
—–
So 8 x 7 = 56
Let us see. one example
Example 3 :.
Suppose we have to find a 9 x 9
First write one below the other
9
9
Then we reduce numbers from 10 and write the value (09/10 = 1; 10-9 = 1) to the desired character with ‘-‘ to between
9 -. 1
7-1
The product has two parts. The first part is Cross difference (here it is 9-1 = 9-1 = 8).
The second part is vertical product the right digits (here it is 1 x 1 = 1)
We write parts separated by a slash
9 – .. 1
9-1
—–
8/1
—–
So 9 x 9 = 81
In the next example, the second part has two numbers
Let’s see how to deal with the issue
Example 4 :. .
To find a 7 x 6
First write one below the other.
7
6
Then we reduce numbers from 10 and write values. (10-7 = 3; 10-6 = 4) to the right of the numbers with a ‘-‘ to between
7-3
6-4
product two parts. The first part is Cross difference (here it is 7-4 = 6-3 = 3).
The second part is vertical product the right digits (here it is 3 x 4 = 12)
We write parts separated by a slash
seven – .. 3
6-4
—–
3/12
—–
Second bit, here are two digits.
of keep the digit unit (2) carry over the number (1) to the left of
seven -. 3
6-4
————–
(3 + 1) / 2 = 4/2
—— ——-
So, the answer will be (3 + 1) / 2 = 4/2
Thus, 7 x 6 = 42.
Example 5 :.
To find the 8 x 3
By following the above procedure, we may write as follows
8-2
3-7
—–
2/14
—–
first part = 8-7 = 3 – 2 = 1
The second part here is 2×7 = 14
It has two digits. of keep the digit unit (4) and carry over the number (1) to the left of
8 -. 2
3-7
————–
(1 + 1) / 4 = 2/4
—– ——–
So, the answer will be (1 + 1) / 4 = 2/4
Thus, 8 x 3 = 24 .
let’s see one last example
Example 6 :.
to find 6 x 5
By following the above procedure, we can write that.
6-4
5-5
—–
1/20
—–
first part = 6-5 = 5-4 = 1
The second part here is 4×5 = 20
It has two digits. of keep the digit unit (0) and carry over the number (2) to the left of
6 -. 4
5-5
————–
(1 + 2) / 0 3/0 =
—– ——–
So, the answer will be (1 + 2) / 0 = 3/0
Thus, 6 x 5 = 30.
Thus, we can come to any value up to 10 x 10
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